4m^2-2m+6=m^2-20m+6

Solution for 4m^2-2m+6=m^2-20m+6 equation:

4m^2-2m+6=m^2-20m+6

We move all terms to the left:

4m^2-2m+6-(m^2-20m+6)=0

We get rid of parentheses

4m^2-m^2-2m+20m-6+6=0

We add all the numbers together, and all the variables

3m^2+18m=0

a = 3; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·3·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*3}=\frac{-36}{6}
=-6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*3}=\frac{0}{6}
=0
$